## Meromorphic Functions on the Riemann Sphere (Pt. I)

**Point of Post: **In this post we classify the meromorphic functions on the Riemann sphere .

**Motivation**

If a random kid off the street asked you “what are the continuous functions ?” or “what are all the smooth maps ?” you would probably replay with a definitive “Ehrm…well…they’re just…” This is because such a description (besides “they’re just the continuous functions!”) is beyond comprehension in those cases! For example, it would take quite a bit of ingenuity to come up with something like the Blancmange function–in fact, such crazy continuous everywhere, differentiable nowhere functions are, in a sense dense in the space of continuous functions.

Thus, it should come as somewhat of a surprise that after reading this post you will be able to answer a kid asking “what are all the meromorphic functions on the Riemann sphere?” with a “Ha, that’s simple. They’re just…”. To be precise, we have already proven that , and we shall now show that the reverse inclusion is true! Now, more generally, we shall be able to give a satisfactory (algebraic!) of the meromorphic functions of any compact Riemann surface. While this won’t be quite as impressive as the explicit, simple characterization of but still a far cry from our situation with trying to characterize , since we don’t really even have an algebraic (ring theoretic) description of this (in terms of more familiar objects). This should be, once again, another indication that the function theory of compact Riemann surfaces is very rigid–they admit meromorphic functions, but not so many that the computation (algebraically) of their meromorphic function field is untenable.

Ok, now that we have had some discussion about the philosophical implications of actually being able to describe let’s discuss how we are actually going to prove . The basic idea comes from the fact that we can actually find a function which has prescribed zeros and poles such that and for any –namely, the function given by . Thus, if is a meromorphic function on with zeroes and poles described as in the last sentence we see that is a meromorphic function on and which has no zeros or poles on . In particular, is a function meromorphic on but holomorphic on , and with no zeros. Now, it’s a common fact from complex analysis that the only entire function with a pole at infinity (recall that the somewhat confusing definition of pole at infinity now makes a lot more sense!) is a polynomial. Thus, is a polynomial, but since has no zeros on we know from the fundamental theorem of algebra that is constant. Thus, is really just a constant multiple of ! Note that the key to this proof is that ability specify poles and zeros of a given multiplicity, except perhaps specifying a pole at infinity, and that the point infinity is well-behaved (in the sense that things that have poles there are pretty tame).

**Meromorphic Functions on **

Ok, let’s now try to make the above argument rigorous:

**Theorem:** *.*

**Proof: **We have already proven that and so it suffices to prove the reverse inclusion. To do this, let . Since is compact we know that the zeros and poles of are finite. To be explicit, let the zeros of in be with , and let the poles of in be with . Now, consider the function given by

Now, we know that is a meromorphic function on (it’s still in !) and since is evidently a ring we see that , which we shall call , is in . Now, by construction for all , and thus we see that is entire, and furthermore has no zeros. Now, since is entire it has a globally valid representation as a Maclaurin series, say

Now, since is mermorphic at , we know that is meromorphic at . Just to be clear, this is because with is a chart at , , and –thus this is the definition of being meromorphic at . That said, we know that locally at one has that

Now, since must have finite order at , we see that, in particular, for sufficiently large –in other words, is a polynomial. That said, we see then that is a polynomial on which, by prior comment, has no zeros on . By the Fundamental Theorem of Algebra, this implies that is constant, say . Thus,

in particular, as desired.

More specifically, the above really proves that a meromorphic function (not presented to us as a rational function in ) is really just the rational function in which has the same poles and zeros as (obviously!).

**References:**

[1] Varolin, Dror. *Riemann Surfaces by Way of Complex Analytic Geometry*. Providence, RI: American Mathematical Society, 2011. Print.

[2] Miranda, Rick. *Algebraic Curves and Riemann Surfaces*. Providence, RI: American Mathematical Society, 1995. Print.

[3] Forster, Otto. *Lectures on Riemann Surfaces*. New York: Springer-Verlag, 1981. Print.

[4] Conway, John B. *Functions of One Complex Variable*. New York: Springer-Verlag, 1978. Print.

[5] Gong, Sheng. *Concise Complex Analysis*. Singapore: World Scientific, 2001. Print

[6] Rudin, Walter. *Real and Complex Analysis.* New York: McGraw-Hill, 1966. Print

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